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Extension of an inequality of Ramanujan
Expositiones Mathematicae ( IF 0.7 ) Pub Date : 2023-02-13 , DOI: 10.1016/j.exmath.2023.02.002
Horst Alzer

We prove that k=1n+k1k1kk2(x+k)n+k<1xn+1holds for all integers n0 and real numbers x>0. This extends a result of Ramanujan, who submitted the inequality with n=0 as a problem to the “Journal of the Indian Mathematical Society”.



中文翻译:

拉马努金不等式的推广

我们证明Σk=1无穷大n+k-1k-1kk-2X+kn+k<1Xn+1对所有整数都成立n0和实数X>0。这扩展了拉马努金的结果,他提出了不等式:n=0作为“印度数学会杂志”的一个问题。

更新日期:2023-02-13
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