Journal of Combinatorial Theory Series B ( IF 1.4 ) Pub Date : 2023-10-20 , DOI: 10.1016/j.jctb.2023.10.003 Tung Nguyen , Alex Scott , Paul Seymour
Let us say a graph is -free, where is an integer, if there do not exist s cycles of the graph that are pairwise vertex-disjoint and have no edges joining them. The structure of such graphs, even when , is not well understood. For instance, until now we did not know how to test whether a graph is -free in polynomial time; and there was an open conjecture, due to Ngoc Khang Le, that -free graphs have only a polynomial number of induced paths.
In this paper we prove Le's conjecture; indeed, we will show that for all , there exists such that every -free graph G has at most induced paths, where is the number of vertices. This provides a poly-time algorithm to test if a graph is -free, for all fixed s.
The proof has three parts. First, there is a short and beautiful proof, due to Le, that reduces the question to proving the same thing for graphs with no cycles of length four. Second, there is a recent result of Bonamy, Bonnet, Déprés, Esperet, Geniet, Hilaire, Thomassé and Wesolek, that in every -free graph G with no cycle of length four, there is a set of vertices that intersects every cycle, with size logarithmic in . And third, there is an argument that uses the result of Bonamy et al. to deduce the theorem. The last is the main content of this paper.
中文翻译:
图中没有反完全循环的诱导路径
假设一个图表是-自由,其中是一个整数,如果图中不存在成对顶点不相交且没有边连接的s 个循环。这种图的结构,即使当,不太理解。例如,直到现在我们还不知道如何测试一个图是否是-多项式时间内自由;Ngoc Khang Le 提出了一个公开的猜想:-自由图仅具有多项式数量的诱导路径。
本文我们证明了Le的猜想;事实上,我们将向所有人证明, 那里存在使得每个-自由图G最多有诱导路径,其中是顶点数。这提供了一个多时间算法来测试图是否是-free,对于所有固定的s。
证明分为三个部分。首先,Le 提供了一个简短而优美的证明,它可以将问题简化为证明没有长度为 4 的循环的图也能证明同样的事情。其次,Bonamy、Bonnet、Déprés、Esperet、Geniet、Hilaire、Thomassé 和 Wesolek 最近的结果表明,在每个- 自由图G,没有长度为 4 的环,有一组与每个环相交的顶点,其大小为对数。第三,有一个论证使用了 Bonamy 等人的结果。推导出定理。最后是本文的主要内容。