Abstract

Solid-liquid phase equilibria of the two ternary systems (LiB₅O₈ + RbB₅O₈ + H₂O) and (NaB₅O₈ + RbB₅O₈ + H₂O) were investigated at T = 308.15 K and p = 0.1 MPa by the isothermal solution equilibrium method. The experimental results show that the phase diagrams of the systems (LiB₅O₈ + RbB₅O₈ + H₂O) and (NaB₅O₈ + RbB₅O₈ + H₂O) at 308.15 K contain one invariant point, two univariant curves and two crystallization regions. The area of the crystallization region of RbB₅O₈·4H₂O is much larger than that of LiB₅O₈·5H₂O in the former system and that of NaB₅O₈·5H₂O in the latter system. Owing to the different solubilities of the salts in the aqueous systems, the solubility of RbB₅O₈ in the solution decreased obviously with the increasing concentration of LiB₅O₈ or NaB₅O₈ in either ternary system, indicating that both have a relatively strong effect on the solubility of RbB₅O₈. It was found that both systems belong to the simple eutectic type, and neither double salts nor solid solutions were formed.

中文翻译：

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三元体系 (LiB5O8 + RbB5O8 + H2O) 和 (NaB5O8 + RbB5O8 + H2O) 在 308.15 K 和 0.1 MPa 下的溶解度、密度和折射率

摘要

两个三元体系的固液相平衡(LiB₅O_{88< /span>88}O₅ 任一三元体系，表明两者对RbB的溶解度都有较强的影响₈O₅ 或 NaBO_{58明显降低}O₅O 在后一个系统中。由于盐在水体系中的溶解度不同，RbB的溶解度₂·5H₈O·4H< /span>原体系中的O和NaB₂·5H₈O₅O 比 LiB 大得多₂₈O₅O) 在 308.15 K 处包含一个不变点、两条单变量曲线和两个结晶区。 RbB结晶区面积₂ + H₈O₅ + RbBO₅O) 和 (NaB + H< /span> + H₈O₅ + RbB₈O₅ = 0.1 MPa。实验结果表明体系的相图(LiBp = 308.15 进行调查通过等温溶液平衡法求得K和TO) 在 ₂ + H₈O₅ + RbB₈O₅O) 和 (NaB₂₈O₅ + RbB